[HbMinecraft マ 1762Reputation⎔ 0CreditsOverlord EditionNukerForum ModeratorOutpost PoliceAdvanced Denizen1979 posts]

Time for some math!

We have an element, let’s call it Schrabidium. It’s the 216th element and has a mass of 312 gramms per mol. How much weights a hammer made out of 6m³ Schrabidium?

 

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Sometimes, I dream about cheese.

[lukep11804 マ 1106Reputation⎔ 0CreditsLeader EditionEliteForum ModeratorOutpost PoliceExpanse BureauAdvanced Denizen3206 posts]

0nim1si wrote:

0nim1si wrote:

lukep11804 wrote:

0nim1si wrote:

i’m bored

And?

that’s it

im not bored anymore, I just finished my English exam so I’m happy

great

∞ lukep11804 ∞

Rival Rebels Favorite Zombie Pigman

[lukep11804 マ 1106Reputation⎔ 0CreditsLeader EditionEliteForum ModeratorOutpost PoliceExpanse BureauAdvanced Denizen3206 posts]

HbMc wrote:

Time for some math! We have an element, let’s call it Schrabidium. It’s the 216th element and has a mass of 312 gramms per mol. How much weights a hammer made out of 6m³ Schrabidium?

Two things one what is it with you and schrabidium two that’s impossible there are only 118 elements and the 216 what that high a mass would make it blow itself apart

 

 

 

∞ lukep11804 ∞

Rival Rebels Favorite Zombie Pigman

[HbMinecraft マ 1762Reputation⎔ 0CreditsOverlord EditionNukerForum ModeratorOutpost PoliceAdvanced Denizen1979 posts]

lukep11804 wrote:

HbMc wrote:

Time for some math! We have an element, let’s call it Schrabidium. It’s the 216th element and has a mass of 312 gramms per mol. How much weights a hammer made out of 6m³ Schrabidium?

Two things one what is it with you and schrabidium two that’s impossible there are only 118 elements and the 216 what that high a mass would make it blow itself apart

I know it doesn’t work, I just wanted to know how to get from g/mol to kg/m³

 

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Sometimes, I dream about cheese.

[lukep11804 マ 1106Reputation⎔ 0CreditsLeader EditionEliteForum ModeratorOutpost PoliceExpanse BureauAdvanced Denizen3206 posts]

HbMc wrote:

lukep11804 wrote:

HbMc wrote:

Time for some math! We have an element, let’s call it Schrabidium. It’s the 216th element and has a mass of 312 gramms per mol. How much weights a hammer made out of 6m³ Schrabidium?

Two things one what is it with you and schrabidium two that’s impossible there are only 118 elements and the 216 what that high a mass would make it blow itself apart

I know it doesn’t work, I just wanted to know how to get from g/mol to kg/m³

Okay well you know that 1000 grams= 1 kilogram so all you need is meters cubed to mol’s which I forgot :/

∞ lukep11804 ∞

Rival Rebels Favorite Zombie Pigman

[Rodol マ 1858Reputation⎔ 0CreditsExpanse BureauAdvanced Denizen3055 posts]

First determine whether the state of matter, I assume solid. Then determine whether it is a metallic substance, or an ionic substance e.g. salt. Since it is only one element, and not a compound, I assume metal. Next get the radius of one atom of the substance, and use a sphere packing formula to see how many spheres with that radius you can fit inside 1 m^3. Multiple the number of atoms by the weigh of each atom. The sphere packing formula depends on the crystal lattice of your substance, for element 216 it is 2 electrons away from a full orbital, so it can only bond with two other atoms. That means you will get a highly stringy substance, pretty much only lines of atoms are valid in this configuration. I guess you can make loops with them or something to hold it together. I would calculate the number of atoms in one string of atoms 1 meter long, then cube that number and multiply by mass per atom.

BTW you will love one of the RR game features.

⋰⋮RODOL⋮⋱

[BroBrine マ 151Reputation⎔ 0CreditsElite EditionLieutenant GeneralOutpost PoliceAdvanced Denizen351 posts]

i don’t even tho whats going on and i’m reading the thread lol oh waint no i get it…

☢William_Brobrine☢

[lukep11804 マ 1106Reputation⎔ 0CreditsLeader EditionEliteForum ModeratorOutpost PoliceExpanse BureauAdvanced Denizen3206 posts]

Got it ;/

∞ lukep11804 ∞

Rival Rebels Favorite Zombie Pigman

[EWMX12 マ 481Reputation⎔ 0CreditsGeneral GeneralAdvanced Denizen520 posts]

Hey there, just exploring the new forums

[lukep11804 マ 1106Reputation⎔ 0CreditsLeader EditionEliteForum ModeratorOutpost PoliceExpanse BureauAdvanced Denizen3206 posts]

Looks good right?

∞ lukep11804 ∞

Rival Rebels Favorite Zombie Pigman

[HbMinecraft マ 1762Reputation⎔ 0CreditsOverlord EditionNukerForum ModeratorOutpost PoliceAdvanced Denizen1979 posts]

Rodol wrote:

First determine whether the state of matter, I assume solid. Then determine whether it is a metallic substance, or an ionic substance e.g. salt. Since it is only one element, and not a compound, I assume metal. Next get the radius of one atom of the substance, and use a sphere packing formula to see how many spheres with that radius you can fit inside 1 m^3. Multiple the number of atoms by the weigh of each atom. The sphere packing formula depends on the crystal lattice of your substance, for element 216 it is 2 electrons away from a full orbital, so it can only bond with two other atoms. That means you will get a highly stringy substance, pretty much only lines of atoms are valid in this configuration. I guess you can make loops with them or something to hold it together. I would calculate the number of atoms in one string of atoms 1 meter long, then cube that number and multiply by mass per atom. BTW you will love one of the RR game features.

Thanks! I did the following: Schrabidium is part of the iron group. Because 3 out of 4 elements of this group have the same crystal structure, I assume Schrabidium has it too. Now we divide the density [g/cm³] by the atomic weight u [g] which leaves us with atoms per cm³ [1/cm³] (I did not use floating point numbers because I’ll go back the same way I came here), being 0,12239; 0,118751 and 0,140997 *10^x 1/cm³ for osmium, ruthenium and iron (Note: It was hassium which had the same structure, but it’s density is unknown so I used iron instead). I take the average (0,12738*10^x 1/cm³) and multiply it by the atomic weight u of Schrabidium (312, a value which isn’t based on statistics, thus probably changing in the future) and we get 39,7424 g/cm³, or almost 40 metric tons per block. Times six and we get a hammer which weighs 238 thousand 455 kilograms. The mighty Mjölnir is said to weigh a sobering 42,3 pounds (not even 20 kilograms, even I* could lift that, and I have noodle arms), which is one twelve thousandth of the Schrabidium hammer’s weight. Does it deserve +1000000000 attack damage? Yes. Do I care about it supposetly being OP? No.

*Not factoring in the Mjölnir’s “be-worthy-to-lift”-property

 

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Sometimes, I dream about cheese.

[HbMinecraft マ 1762Reputation⎔ 0CreditsOverlord EditionNukerForum ModeratorOutpost PoliceAdvanced Denizen1979 posts]

Also, my roommate won’t stop lying in my bed staring on my screen asking questions, can you repost that screenshot of the player model you showed us about half a year ago?

 

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Sometimes, I dream about cheese.

[lukep11804 マ 1106Reputation⎔ 0CreditsLeader EditionEliteForum ModeratorOutpost PoliceExpanse BureauAdvanced Denizen3206 posts]

Maybe your roommate should join RR

∞ lukep11804 ∞

Rival Rebels Favorite Zombie Pigman

[lukep11804 マ 1106Reputation⎔ 0CreditsLeader EditionEliteForum ModeratorOutpost PoliceExpanse BureauAdvanced Denizen3206 posts]

HbMc wrote:

Rodol wrote:

First determine whether the state of matter, I assume solid. Then determine whether it is a metallic substance, or an ionic substance e.g. salt. Since it is only one element, and not a compound, I assume metal. Next get the radius of one atom of the substance, and use a sphere packing formula to see how many spheres with that radius you can fit inside 1 m^3. Multiple the number of atoms by the weigh of each atom. The sphere packing formula depends on the crystal lattice of your substance, for element 216 it is 2 electrons away from a full orbital, so it can only bond with two other atoms. That means you will get a highly stringy substance, pretty much only lines of atoms are valid in this configuration. I guess you can make loops with them or something to hold it together. I would calculate the number of atoms in one string of atoms 1 meter long, then cube that number and multiply by mass per atom. BTW you will love one of the RR game features.

Thanks! I did the following: Schrabidium is part of the iron group. Because 3 out of 4 elements of this group have the same crystal structure, I assume Schrabidium has it too. Now we divide the density [g/cm³] by the atomic weight u [g] which leaves us with atoms per cm³ [1/cm³] (I did not use floating point numbers because I’ll go back the same way I came here), being 0,12239; 0,118751 and 0,140997 *10^x 1/cm³ for osmium, ruthenium and iron (Note: It was hassium which had the same structure, but it’s density is unknown so I used iron instead). I take the average (0,12738*10^x 1/cm³) and multiply it by the atomic weight u of Schrabidium (312, a value which isn’t based on statistics, thus probably changing in the future) and we get 39,7424 g/cm³, or almost 40 metric tons per block. Times six and we get a hammer which weighs 238 thousand 455 kilograms. The mighty Mjölnir is said to weigh a sobering 42,3 pounds (not even 20 kilograms, even I* could lift that, and I have noodle arms), which is one twelve thousandth of the Schrabidium hammer’s weight. Does it deserve +1000000000 attack damage? Yes. Do I care about it supposetly being OP? No. *Not factoring in the Mjölnir’s “be-worthy-to-lift”-property

Make weapons with the you know what in your mod

∞ lukep11804 ∞

Rival Rebels Favorite Zombie Pigman

[Rodol マ 1858Reputation⎔ 0CreditsExpanse BureauAdvanced Denizen3055 posts]

You mean the one with the exoskeleton? Its no longer relevant, I changed the player concept like 5 times since then.

⋰⋮RODOL⋮⋱

[EWMX12 マ 481Reputation⎔ 0CreditsGeneral GeneralAdvanced Denizen520 posts]

Hey guys, i have something to tell you,

Yesterday is was  exploring on the internet, normally, but then a windows 10 window appeared, I said “This thing again, I HATE WINDOWS 10” i closed the window and keep on my duties, 10 minutes later my computer turned off “WHAT THE… why to me!?” I just said that but then appeared a message that said “Preparing to install windows 10” “NO NO NO!!!, HOW IS THIS POSSIBLE!!!??” I EXPLODED!! i thought it was a virus that tried to make me a bad joke, OMG!!! I HATE MY LIFE!! “0%”

“NONNONONO EVERYTHING LESS THAN WINDOWS 10”

God, i tried to keep the calm, the update would be very long, at least 2 hours, so i went to sleep, next day i found my computer with the message “Welcome to Windows 10”

So what i really want to tell you all is that you never ignore ANY windows that want to make you install that, because sometimes THEY FORCE YOU to install something WITHOUT YOUR PERMISSION

And also if you have windows 10, you are giving all your personnal information to microsoft, because windows 10 is for that, the worst part is that there is a keylogger installed in windows, yes, a KEYLOGGER, one of the worst virusses of all, but its easy to delete it

 

[lukep11804 マ 1106Reputation⎔ 0CreditsLeader EditionEliteForum ModeratorOutpost PoliceExpanse BureauAdvanced Denizen3206 posts]

Interesting story

∞ lukep11804 ∞

Rival Rebels Favorite Zombie Pigman

[HbMinecraft マ 1762Reputation⎔ 0CreditsOverlord EditionNukerForum ModeratorOutpost PoliceAdvanced Denizen1979 posts]

Three things:

1. Windows does not automatically install the new OS, you must have clicked on the window, otherwise nothing would have happened.

2. Because of the offer, it seems like you already have windows 8 or 8.1. 10 is just like it, but it got rid of the app tiles no one ever liked.

3. If you are afreaid of companies having your personal information, it’s already too late. About all OS’ (including phones) will collect your data, google already has them, and so do the advertisment companies. Welcome to the 21st century, where secrets aren’t secret (except if you use strong encyption, veracrypt or something like that)

 

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Sometimes, I dream about cheese.

[HbMinecraft マ 1762Reputation⎔ 0CreditsOverlord EditionNukerForum ModeratorOutpost PoliceAdvanced Denizen1979 posts]

:(

 

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Sometimes, I dream about cheese.

[HbMinecraft マ 1762Reputation⎔ 0CreditsOverlord EditionNukerForum ModeratorOutpost PoliceAdvanced Denizen1979 posts]

The what?

 

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Sometimes, I dream about cheese.

[Rodol マ 1858Reputation⎔ 0CreditsExpanse BureauAdvanced Denizen3055 posts]

No, ElWither is right, look at this: Microsoft U-turn on ‘nasty trick’ pop-up

⋰⋮RODOL⋮⋱

[HbMinecraft マ 1762Reputation⎔ 0CreditsOverlord EditionNukerForum ModeratorOutpost PoliceAdvanced Denizen1979 posts]

wat

 

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Sometimes, I dream about cheese.

[HbMinecraft マ 1762Reputation⎔ 0CreditsOverlord EditionNukerForum ModeratorOutpost PoliceAdvanced Denizen1979 posts]

Can you post a newer screenshot pretty please? :3

 

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Sometimes, I dream about cheese.

[0nim1si マ 430Reputation⎔ 0CreditsPilotOutpost PoliceAdvanced Denizen1053 posts]

I’m not op on any servers, and I also need to get all of the new rod disk codes

<html> <body> <img src=\"http://imgh.us/RR2016.png\" alt=\"http://imgh.us/RR_soccer_game_1.png\" style=\"width:720px;height:275px;\"> </body> </html>

[0nim1si マ 430Reputation⎔ 0CreditsPilotOutpost PoliceAdvanced Denizen1053 posts]

maybe not all of them but rodol’s one at least

<html> <body> <img src=\"http://imgh.us/RR2016.png\" alt=\"http://imgh.us/RR_soccer_game_1.png\" style=\"width:720px;height:275px;\"> </body> </html>